f(5) means to go to the equation for f(x) and replace all the x’s with 5. When you do, then you get:.. Similarly, h(5) means to go to the equation for h(x) and replace all the x’s by 5. And when you, make this substitution you get:.. so adding f(5) to h(5) is equal to and the result is zero.. So the answer to your problem is zero..
A Letter-Equations brain teaser titled ‘5 F on a H’ : 5 F on a H. Letter-Equations Letter Equations are well known phrases or facts where the key words have been replaced with the first letter of that word. These are often in the form of an equation, which contain a number, an = …
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2.1 Solve -fghor+3f-2g-5 = 0 In this type of equations, having more than one variable (unknown), you have to specify for which variable you want the equation solved. We shall not handle this type of equations at this time.
Pre-Algebra. Solve for f c=5/9*(f-32) Since is on the right side of the equation, switch the sides so it is on the left side of the equation. Simplify the left side.
Feb 25, 2008 · solve for the function f(x+h)-f(x)/h for the function x^2-6x+4. Upload failed. Please upload a file larger than 100×100 pixels; We are experiencing some problems, please try again.
Sep 15, 2012 · Best Answer: Your first problem (solving for F): You don’t have to learn the formula like Mr. T. says; if you have the formula of C, you can get it for F at this way: You want to separate F. For this you can first multiply both sides with 9/5, because then you get rid of the 5/9 on the right side (5/9 times
You can put this solution on YOUR website! A=1/2bh Solve for h.. The idea is to isolate the variable ‘h’ to one side of the equation — doesn’t matter which side.. Starting with: A=1/2bh
Calculus. Find the Difference Quotient f(x)=1/x. Consider the difference quotient formula. Use this formula to solve for the slope of the secant line. Find the components of the definition. Tap for more steps Evaluate the function at . Tap for more steps Replace the variable with in the expression.
In the result above, notice that f (x + h) – f (x) does not equal f (x + h – x) = f (h). You cannot “simplify” the different functions’ arguments in this manner. Addition or subtraction of functions is not the same as addition or subtraction of the functions’ arguments. Again, the parentheses in function notation do not indicate multiplication.
Solve the following equation for f: h = pf/(f+pt) (self.cheatatmathhomework) submitted 3 years ago by [deleted] I keep racking my brain over it (it seems fairly simple) but I’ve been out of algebra for awhile and I can’t seem to come up with the answer.